PSY 429 Experimental Psychology

Class Exercise #2

Standard Scores (z scores)

Answers

 

 

1. What is the mean and standard deviation of a z-score distribution?

 The mean is 0 and the standard deviation is 1.0

2. What is the z-score formula for a population?

  z = (X - m ) / s
 

3. What is the z-score formula for a sample?

 z = (X - M ) / s

4. A distribution of general psychology test scores has a mean of m = 60 and a standard deviation of s = 4. What is the z-score for Scott who received a 66? (Assume the distribution of test scores was normal.)

 z = (X - m ) / s

z = 66 - 60 / 4

z = 1.5

 

5. What proportion of scores lies above Scott's score of 66?

[See Table 2]

 .0668 or 6.68% of scores lies above a score of 66

6. The distribution of SAT verbal scores for high school seniors has a mean of m = 500 and a standard deviation of s = 100. Joe took the SAT and scored 430 on the verbal subtest. What is the z-score which corresponds to Joe's score of 430?

z = (X - m ) / s

z = 430 - 500 / 100

z = - .70

a. What percentage of people fell below Joe?

[See Table 2]

.2420 or 24.2% of the scores fell below Joe's score of 66

b. What percentage of people fell above Joe?

[See Table 2]

 .7580 or 75.8% of the scores fell above Joe's score of 66

7. Given a normally distributed variable with a m = 50 and a s = 10, what proportion of scores falls below a score of 30?

z = (X - m ) / s

z = 30 - 50 / 10

z = - 2.00

[See Table 2]

Therefore, .0228 or 2.28% of scores falls below a score of 30.

8. Given a normally distributed variable with a m = 50 and a s = 10, what proportion of scores falls between a score of 40 and a score of 55?

 z = (X - m ) / s

z = 40 - 50 / 10

z = - 1.00

[See Table 2]

Therefore, .3413 or 34.13% of scores lie between a score of 40 and the mean.

z = (X - m ) / s

z = 55 - 50 / 10

z = .50

[See Table 2]

Therefore, .1915 or 19.15% of scores lie between a score of 55 and the mean.

Consequently, 53.28% (34.13% + 19.15%) of scores lie between a score of 40 and a score of 55.

9. Given a normal distribution of a sample with a M = 48 and a S = 10 and an n = 300, find the number of cases that would fall below a score of 44.

 z = (X - M ) / s

z = 44 - 48 / 10

z = - .40

[See Table 2]

.3446 or 34.46% of scores fall below a score of 44.

To find the number of cases below a score of 44, multiply .3446 by 300.

.3446 x 300 = 103.38 or 103 cases fall below a score of 44.

10. Given a normally distributed variable with a M = 50 and a S = 10, what proportion of scores falls between a score of 35 and a score of 40?

  z = (X - M ) / s

z = 35 - 50 / 10

z = - 1.50

[See Table 2]

Therefore, .4332 or 43.32% of scores lie between a score of 35 and the mean.

z = (X - M ) / s

z = 40 - 50 / 10

z = - 1.00

[See Table 2]

Therefore, .3413 or 34.13% of scores lie between a score of 40 and the mean.

Consequently, .0919 (43.32% - 34.13%) of scores lie between a score of 35 and a score of 40.

11.Find the score that separates the upper 20% from the lower 80% if the mean is 50 and the standard deviation is 10.

20% of scores lie above this score (X)

Find z score associated with upper 20%.

[See Table 2]

Looking at z table, the z score associated with the upper 20% is .84.

Given the formula z = (X - m ) / s

then X = m + z(s)

X = 50 + .84(10)

X = 58.4


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